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-4x^2+19x+11=0
a = -4; b = 19; c = +11;
Δ = b2-4ac
Δ = 192-4·(-4)·11
Δ = 537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{537}}{2*-4}=\frac{-19-\sqrt{537}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{537}}{2*-4}=\frac{-19+\sqrt{537}}{-8} $
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